JEE Main · PhysicsHard
An inductor of inductance $L$ and a resistor of resistance $R$ are connected in series to an AC source of voltage $V = V_0 \sin(\omega t)$. The current in the circuit is $I = I_0 \sin(\omega t - \phi)$. The value of $\tan(\phi)$ is:
- A.$\omega L / R$
- B.$R / (\omega L)$
- C.$\omega R / L$
- D.$L / (\omega R)$
Show correct answer & step-by-step solution
Correct answer: A — $\omega L / R$
Solution
In an LR series circuit, the phase angle is given by . Substituting , we get .
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