JEE Main · PhysicsMedium
An AC voltage $V = 100 \sin(100t)$ is applied to a capacitor of $1 \text{ } \mu\text{F}$. What is the peak current in the circuit?
- A.$0.01 \text{ A}$
- B.$0.1 \text{ A}$
- C.$1 \text{ A}$
- D.$10 \text{ A}$
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Correct answer: A — $0.01 \text{ A}$
Solution
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