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$An inductor of 1 H is connected to a 200 V, 50 Hz AC supply. The current flowing through the inductor is:$

A. $0.636 A$
B. $1.27 A$
C. $0.318 A$
D. $2.0 A$

Show correct answer & step-by-step solution

Correct answer: A — $0.636 A$

Solution

X_{L} = 2 π f L = 2 \times 3.14 \times 50 \times 1 = 314 Ω . Current I = V / X_{L} = 200/314 \approx 0.636 A .

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