In a pure inductive circuit, what is the phase relationship between the voltage and the current?

Solution

1. In a pure inductor, the voltage across the component is proportional to the rate of change of current, expressed as $v=L\frac{di}{dt}$.
2. This relationship causes the current to lag behind the voltage by a phase angle of $90^{\circ }$ or $\frac{\pi }{2}$ radians.
3. Consequently, the voltage leads the current by $90^{\circ }$.
4. Hence the answer is (B).