A car starts from rest and moves with a constant acceleration of 2 meters per second squared. What is the velocity of the car after 5 seconds?

B. 10 m/s — Using the first equation of motion, v = u + at, where u is 0, a is 2, and t is 5. Substituting these values gives v = 0 + 2 * 5 = 10 m/s.

JEE Main · PhysicsEasy

$A car starts from rest and moves with a constant acceleration of $a = 2 \text{ m/s}^2$. What is the velocity of the car after $t = 5 \text{ s}$?$

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Correct answer: B — $10 \text{ m/s}$

Using the first equation of motion,

v = u + a t

, where

u = 0 m/s

a = 2 m/s^{2}

, and

t = 5 s

. Substituting these values gives

v = 0 + (2) (5) = 10 m/s