A particle starts from rest and accelerates at 3 meters per second squared. How much distance does it cover in 2 seconds?

B. 6 m — Using the kinematic equation s equals ut plus one half at squared, with u equal to 0, a equal to 3, and t equal to 2. This gives s equals 0 plus 0.5 times 3 times 4, which is 6 meters.

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$A particle starts from rest ($u = 0$) and accelerates at $a = 3 \text{ m/s}^2$. How much distance does it cover in $t = 2 \text{ s}$?$

A. $3 \text{ m}$
B. $6 \text{ m}$
C. $9 \text{ m}$
D. $12 \text{ m}$

Show correct answer & step-by-step solution

Correct answer: B — $6 \text{ m}$

Solution

Using

s = u t + (1/2) a t^{2}

, with

u = 0

a = 3 m/s^{2}

, and

t = 2 s

. This gives

s = 0 + (0.5) (3) (2^{2}) = 6 m

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