JEE Main · PhysicsHard
Two particles are projected simultaneously from the same point with velocities $v_1$ and $v_2$ at angles $\alpha$ and $\beta$ with the horizontal. If they collide in mid-air, what is the condition on their velocities and angles?
- A.$v_1 \cos \alpha = v_2 \cos \beta$
- B.$v_1 \sin \alpha = v_2 \sin \beta$
- C.$v_1 \tan \alpha = v_2 \tan \beta$
- D.$\frac{v_1}{\cos \alpha} = \frac{v_2}{\cos \beta}$
Show correct answer & step-by-step solution
Correct answer: A — $v_1 \cos \alpha = v_2 \cos \beta$
Solution
For collision, the horizontal positions must be equal at time , so . This implies .
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