JEE Main · PhysicsMedium

$Two blocks of masses $m_1 = 3 \text{ kg}$ and $m_2 = 2 \text{ kg}$ are connected by a light string passing over a frictionless pulley. The system is released from rest. What is the tension $T$ in the string? (Take $g = 10 \text{ m/s}^2$)$

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Correct answer: B — $24 \text{ N}$

Solution

The acceleration of the system is

a = \frac{( m _{1} - m _{2} ) g}{m _{1} + m _{2}} = \frac{( 3 - 2 ) \times 10}{5} = 2 m/s^{2}

. The tension is given by

T = \frac{2 m _{1} m _{2} g}{m _{1} + m _{2}} = \frac{2 \times 3 \times 2 \times 10}{5} = 24 N