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A block of mass $m = 5 \text{ kg}$ is placed on a rough horizontal surface with coefficient of static friction $\mu_s = 0.4$. A horizontal force of $F = 15 \text{ N}$ is applied to the block. What is the frictional force $f$ acting on the block? (Take $g = 10 \text{ m/s}^2$)
- A.$15 \text{ N}$
- B.$20 \text{ N}$
- C.$10 \text{ N}$
- D.$5 \text{ N}$
Show correct answer & step-by-step solution
Correct answer: A — $15 \text{ N}$
Solution
The maximum static friction is calculated as . Since the applied force of is less than the maximum static friction, the block remains at rest and the static friction equals the applied force.
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