A monkey of mass 15 kg climbs a rope which can withstand a maximum tension of 200 N. What is the maximum acceleration with which the monkey can climb up the rope?

C. 3.33 m/s^2 — Using Newton's second law for the monkey, T - mg = ma. Substituting the maximum tension, 200 - 150 = 15a, which gives a = 50 / 15 = 3.33 m/s^2.

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$A monkey of mass m = 15 kg climbs a rope which can withstand a maximum tension of T_{max} = 200 N . What is the maximum acceleration a with which the monkey can climb up the rope? (Take g = 10 m/s^{2})$

A. $1.33 m/s^{2}$
B. $2.5 m/s^{2}$
C. $3.33 m/s^{2}$
D. $5.0 m/s^{2}$

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Correct answer: C — $3.33 m/s^{2}$

Solution

Using Newton's second law, T - m g = ma . Substituting T = 200 N, m = 15 kg, and g = 10 m/s^{2}, we get $200 - 150 = 15a$, so a = \frac{50}{15} = 3.33 m/s^{2} .

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A monkey of mass m=15 kg climbs a rope which can withstand a maximum tension of Tmax​=200 N. What is the maximum acceleration a with which the monkey can climb up the rope? (Take g=10 m/s2)

Solution

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More Laws of Motion practice questions

$A monkey of mass m = 15 kg climbs a rope which can withstand a maximum tension of T_{max} = 200 N . What is the maximum acceleration a with which the monkey can climb up the rope? (Take g = 10 m/s^{2})$