JEE Main · PhysicsMedium
A solenoid of length $L = 0.5 \text{ m}$ has $N = 500$ turns and carries a current $I = 2 \text{ A}$. The magnetic field $B$ at the center of the solenoid is:
- A.$8\pi \times 10^{-4} \text{ T}$
- B.$4\pi \times 10^{-4} \text{ T}$
- C.$2\pi \times 10^{-4} \text{ T}$
- D.$16\pi \times 10^{-4} \text{ T}$
Show correct answer & step-by-step solution
Correct answer: A — $8\pi \times 10^{-4} \text{ T}$
Solution
The magnetic field inside along solenoid is , where . Here , so .
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