JEE Main · PhysicsHard
A thin circular ring of radius $R$ and mass $M$ carries a charge $q$ uniformly distributed over its circumference. The ring is rotated about its axis with a constant angular velocity $\omega$. Find the ratio of the magnetic moment $\mu$ to the angular momentum $L$ of the ring.
- A.$\frac{q}{2M}$
- B.$\frac{q}{M}$
- C.$\frac{2q}{M}$
- D.$\frac{q}{4M}$
Show correct answer & step-by-step solution
Correct answer: A — $\frac{q}{2M}$
Solution
The magnetic moment is . The angular momentum is . Thus, .
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