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What is the magnetic field $B$ at the center of a circular coil of radius $R$ carrying current $I$?
- A.$B = \frac{\mu_0 I}{2R}$
- B.$B = \frac{\mu_0 I}{4R}$
- C.$B = \frac{\mu_0 I}{2\pi R}$
- D.$B = \mu_0 I R$
Show correct answer & step-by-step solution
Correct answer: A — $B = \frac{\mu_0 I}{2R}$
Solution
Using the Biot-Savart law for a circular loop, the magnetic field at the center is derived as . This is a standard result for a single turn coil.
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