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A particle executes simple harmonic motion with an amplitude of $A = 5 \text{ cm}$ and a time period of $T = 2 \text{ s}$. What is the maximum velocity of the particle in $\text{cm/s}$?
- A.$5\pi$
- B.$2.5\pi$
- C.$10\pi$
- D.$2\pi$
Show correct answer & step-by-step solution
Correct answer: A — $5\pi$
Solution
The maximum velocity in simple harmonic motion is given by the formula , where . Substituting the given values, .
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