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A simple pendulum has a time period of $T = 4 \text{ s}$ on Earth. If it is taken to a planet where the acceleration due to gravity is $g' = \frac{g}{4}$, what will be its new time period $T'$?

  1. A.$2 \text{ s}$
  2. B.$4 \text{ s}$
  3. C.$8 \text{ s}$
  4. D.$16 \text{ s}$
Show correct answer & step-by-step solution

Correct answer: C$8 \text{ s}$

Solution

The time period of a simple pendulum is . Since , if , then .

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