A transverse wave is described by the equation y equals 0.05 sin(2x minus 4t). What is the wave speed?

C. 2 m/s — The wave equation is in the form y = A (kx - t). The wave speed is given by v = k. Here, = 4 and k = 2, so v = 42 = 2 m/s.

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$A transverse wave is described by the equation $y = 0.05 \sin(2x - 4t)$, where $x$ and $y$ are in meters and $t$ is in seconds. What is the wave speed $v$?$

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Correct answer: C — $2 \text{ m/s}$

The wave equation is in the form

y = A sin (k x - ω t)

. The wave speed is given by

v = \frac{ω}{k}

. Here,

ω = 4 rad/s

and

k = 2 rad/m

, so

v = \frac{4}{2} = 2 m/s