A torque of 10 Newton meters is applied to a body with a moment of inertia of 2 kilogram meters squared. What is the angular acceleration in radians per second squared?

C. 5 — According to Newton's second law for rotation, torque equals moment of inertia times angular acceleration. Therefore, angular acceleration is torque divided by moment of inertia, which is 10 divided by 2.

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$A torque of τ = 10 Nm is applied to a body with a moment of inertia of I = 2 kg m^{2} . What is the angular acceleration α in rad/s^{2} ?$

A. $20$
B. $10$
C. $5$
D. $2$

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Correct answer: C — $5$

Solution

According to Newton's second law for rotation, τ = I α . Therefore, α = \frac{τ}{I} = \frac{10}{2} = 5 rad/s^{2} .

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A torque of τ=10 Nm is applied to a body with a moment of inertia of I=2 kg m2. What is the angular acceleration α in rad/s2?

Solution

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More Rotational Motion practice questions

$A torque of τ = 10 Nm is applied to a body with a moment of inertia of I = 2 kg m^{2} . What is the angular acceleration α in rad/s^{2} ?$