If the angular velocity of a rotating body increases from 2 radians per second to 6 radians per second in 2 seconds, what is the angular acceleration in radians per second squared?

B. 2 — Angular acceleration is defined as the change in angular velocity divided by the time taken. Here, the change is 6 minus 2, which is 4, and dividing by 2 seconds gives 2 radians per second squared.

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$If the angular velocity of a rotating body increases from ω_{i} = 2 rad/s to ω_{f} = 6 rad/s in t = 2 s, what is the angular acceleration α in rad/s^{2} ?$

A. $1$
B. $2$
C. $3$
D. $4$

Show correct answer & step-by-step solution

Correct answer: B — $2$

Solution

Angular acceleration is defined as α = \frac{ω _{f} - ω _{i}}{t} . Here, α = \frac{6 - 2}{2} = \frac{4}{2} = 2 rad/s^{2} .

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If the angular velocity of a rotating body increases from ωi​=2 rad/s to ωf​=6 rad/s in t=2 s, what is the angular acceleration α in rad/s2?

Solution

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More Rotational Motion practice questions

$If the angular velocity of a rotating body increases from ω_{i} = 2 rad/s to ω_{f} = 6 rad/s in t = 2 s, what is the angular acceleration α in rad/s^{2} ?$