For a common base transistor circuit, the current amplification factor is 0.95. If the emitter current is 1 mA, the base current is

A. 0.05 , mA — The collector current is I_c = I_e = 0.95 1 = 0.95 , mA. Since I_e = I_c + I_b, the base current is I_b = I_e - I_c = 1 - 0.95 = 0.05 , mA.

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$For a common base transistor circuit, the current amplification factor is α = 0.95 . If the emitter current is I_{e} = 1 mA, the base current I_{b} is$

A. $0.05 mA$
B. $0.95 mA$
C. $0.01 mA$
D. $0.1 mA$

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Correct answer: A — $0.05 mA$

Solution

Given α = \frac{I _{c}}{I _{e}} = 0.95, then I_{c} = 0.95 mA . Using I_{e} = I_{c} + I_{b}, we get I_{b} = 1 - 0.95 = 0.05 mA .

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For a common base transistor circuit, the current amplification factor is α=0.95. If the emitter current is Ie​=1mA, the base current Ib​ is

Solution

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More Semiconductor Devices practice questions

$For a common base transistor circuit, the current amplification factor is α = 0.95 . If the emitter current is I_{e} = 1 mA, the base current I_{b} is$