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A nucleus with mass number $A = 240$ breaks into two fragments each of mass number $A = 120$. If the binding energy per nucleon of the parent nucleus is $7.6$ MeV and that of the fragments is $8.5$ MeV, what is the total energy released?
- A.$216$ MeV
- B.$108$ MeV
- C.$432$ MeV
- D.$864$ MeV
Show correct answer & step-by-step solution
Correct answer: A — $216$ MeV
Solution
Energy released = (Total BE of products) - (Total BE of reactant). Energy = MeV.
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