JEE Main · PhysicsMedium
The de Broglie wavelength $\lambda$ of an electron accelerated through a potential difference of $V = 100$ V is approximately:
- A.$0.123$ nm
- B.$1.23$ nm
- C.$0.0123$ nm
- D.$12.3$ nm
Show correct answer & step-by-step solution
Correct answer: A — $0.123$ nm
Solution
The de Broglie wavelength for an electron is given by nm. Substituting , we get nm.
Attempt this question & track your score
Sign up free to answer, get instant scoring, and let SolveGini track which Physics topics you need to revise.
Attempt & Track Free →More Modern Physics practice questions
- The energy of a photon with frequency nu is given by which of the following expressions?
- What is the value of the work function for a metal surface if the threshold frequency is 5 times 10 to the power 14 Hert
- In the Bohr model of the hydrogen atom, what is the angular momentum of an electron in the first orbit?
- Which of the following particles has the longest de Broglie wavelength if they all move with the same velocity?
- What is the half-life of a radioactive substance if its decay constant is 0.693 per second?
- A radioactive sample has a half-life of 20 days. What fraction of the original sample will remain undecayed after 100 da
- In a photoelectric effect experiment, the stopping potential for a metal surface is 2.0 V when light of wavelength 300 n
- An electron in a hydrogen atom jumps from the third excited state to the ground state. What is the wavelength of the emi
- A nucleus with mass number 240 breaks into two fragments each of mass number 120. If the binding energy per nucleon of t
- A hydrogen-like atom with atomic number Z is in an excited state of principal quantum number n. It emits a photon of wav
- A radioactive sample decays with a decay constant lambda. The time required for the activity to decrease from A0 to A0/e
- An electron in a hydrogen atom makes a transition from the n=3 state to the n=1 state. The recoil velocity of the hydrog