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An electron in a hydrogen atom jumps from the third excited state ($n = 4$) to the ground state ($n = 1$). What is the wavelength $\lambda$ of the emitted photon? (Take $R = 1.097 \times 10^7$ m$^{-1}$)

  1. A.$97.2$ nm
  2. B.$102.6$ nm
  3. C.$121.6$ nm
  4. D.$91.2$ nm
Show correct answer & step-by-step solution

Correct answer: A$97.2$ nm

Solution

Using the Rydberg formula , with and , we get . Solving for gives approximately nm.

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