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In a photoelectric effect experiment, the stopping potential for a metal surface is $V_s = 2.0$ V when light of wavelength $\lambda = 300$ nm is used. What is the work function $\Phi$ of the metal? (Take $hc = 1240$ eV nm)

  1. A.$1.13$ eV
  2. B.$2.13$ eV
  3. C.$3.13$ eV
  4. D.$4.13$ eV
Show correct answer & step-by-step solution

Correct answer: B$2.13$ eV

Solution

Using Einstein's photoelectric equation, the energy of the incident photon is eV. The work function is eV.

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