A simple pendulum of length 1 meter has a time period of approximately how many seconds?

B. 2 s — The time period of a simple pendulum is given by T = 2 * pi * sqrt(L / g). Substituting L = 1 and g = pi^2, we get T = 2 * pi * sqrt(1 / pi^2) = 2 * pi * (1 / pi) = 2 seconds.

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$A simple pendulum of length L = 1 m has a time period of approximately how many seconds? (Take g = π^{2} m/s^{2})$

A. $1 s$
B. $2 s$
C. $3 s$
D. $4 s$

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Correct answer: B — $2 s$

Solution

The time period of a simple pendulum is given by T = 2 π \frac{L}{g} . Substituting L = 1 and g = π^{2}, we get T = 2 π \frac{1}{π ^{2}} = 2 π \times \frac{1}{π} = 2 s .

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A simple pendulum of length L=1 m has a time period of approximately how many seconds? (Take g=π2 m/s2)

Solution

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More Oscillations & Waves practice questions

$A simple pendulum of length L = 1 m has a time period of approximately how many seconds? (Take g = π^{2} m/s^{2})$