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For a common base transistor circuit, the current amplification factor is $\alpha = 0.95$. If the emitter current is $I_e = 1 \, \text{mA}$, the base current $I_b$ is
- A.$0.05 \, \text{mA}$
- B.$0.95 \, \text{mA}$
- C.$0.01 \, \text{mA}$
- D.$0.1 \, \text{mA}$
Show correct answer & step-by-step solution
Correct answer: A — $0.05 \, \text{mA}$
Solution
Given , then . Using , we get .
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