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A parallel plate capacitor has area $A = 0.01 \text{ m}^2$ and separation $d = 0.001 \text{ m}$. With a dielectric constant $K = 5$, calculate the capacitance $C$. (Use $\epsilon_0 = 8.85 \times 10^{-12} \text{ F/m}$)
- A.$4.425 \times 10^{-10} \text{ F}$
- B.$8.85 \times 10^{-10} \text{ F}$
- C.$2.21 \times 10^{-10} \text{ F}$
- D.$1.77 \times 10^{-10} \text{ F}$
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Correct answer: A — $4.425 \times 10^{-10} \text{ F}$
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