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Two point charges of $q_1 = 2 \times 10^{-6} \text{ C}$ and $q_2 = 8 \times 10^{-6} \text{ C}$ are placed $12 \text{ cm}$ apart. The location of the neutral point where the electric field is zero is at a distance of:
- A.$4 \text{ cm}$ from the $2 \text{ } \mu\text{C}$ charge
- B.$8 \text{ cm}$ from the $2 \text{ } \mu\text{C}$ charge
- C.$6 \text{ cm}$ from the $2 \text{ } \mu\text{C}$ charge
- D.$2 \text{ cm}$ from the $2 \text{ } \mu\text{C}$ charge
Show correct answer & step-by-step solution
Correct answer: A — $4 \text{ cm}$ from the $2 \text{ } \mu\text{C}$ charge
Solution
The electric field is zero at a point where the magnitudes of the fields due to both charges are equal. Using the formula , we find the distance from the smaller charge to be .
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