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Two point charges of $q_1 = 4 \times 10^{-6} \text{ C}$ and $q_2 = -2 \times 10^{-6} \text{ C}$ are separated by a distance of $1 \text{ m}$. At what distance $x$ from $q_1$ on the line joining them will the electric potential be zero?
- A.$0.33 \text{ m}$
- B.$0.50 \text{ m}$
- C.$0.67 \text{ m}$
- D.$0.75 \text{ m}$
Show correct answer & step-by-step solution
Correct answer: C — $0.67 \text{ m}$
Solution
The potential . Substituting values, $4/x = 2/(1-x)$, which simplifies to $4 - 4x = 2x$, yielding .
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