In a photoelectric effect experiment, the stopping potential depends on which of the following?

Solution

1. Einstein's photoelectric equation is given by $K_{max}=h\nu -\Phi$, where $K_{max}$ is the maximum kinetic energy, $h$ is Planck's constant, $\nu$ is the frequency, and $\Phi$ is the work function.
2. The stopping potential $V_s$ is related to the maximum kinetic energy by the equation $e{V}_s=K_{max}$.
3. Substituting the first equation into the second, we get $e{V}_s=h\nu -\Phi$, showing that $V_s$ is a function of the frequency $\nu$.
4. Hence the answer is (B).