What is the energy of a photon with a frequency of $\nu =5\times 10^{14}\text{ Hz}$? (Given: $h=6.63\times 10^{-34}\text{ J s}$)

Solution

1. The energy of a photon is $E=h\nu$.
2. Substitute the given values: $E=(6.63\times 10^{-34}\text{ J s})(5\times 10^{14}\text{ Hz})$.
3. Perform the multiplication: $E=33.15\times 10^{-20}\text{ J}$.
4. Express in standard form: $E=3.315\times 10^{-19}\text{ J}$.
5. Hence the answer is (A).