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$Which of the following particles has the largest de Broglie wavelength if they all have the same kinetic energy?$

A. $Electron$
B. $Proton$
C. $Alpha particle$
D. $Neutron$

Show correct answer & step-by-step solution

Correct answer: A — $Electron$

Solution

The de Broglie wavelength is given by λ = h / p . Since kinetic energy K = p^{2} / (2 m), we have p = 2 m K, meaning wavelength is inversely proportional to the square root of mass; thus, the lightest particle has the longest wavelength.

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