A Zener diode with a breakdown voltage of 10 V is connected in a voltage regulator circuit with a series resistance of 200 ohm and a load resistance of 1 kilo-ohm. If the input voltage is 15 V, what is the current through the Zener diode?

A. 0.015 , A — The total current from the source is (V_in - V_z) / R_s = (15 - 10) / 200 = 0.025 A. The load current is V_z / R_L = 10 / 1000 = 0.010 A, so the Zener current is 0.025 - 0.010 = 0.015 A.

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$A Zener diode with a breakdown voltage of V_{z} = 10 V is connected in a voltage regulator circuit with a series resistance R_{s} = 200 Ω and a load resistance R_{L} = 1 k Ω . If the input voltage is V_{in} = 15 V, what is the current through the Zener diode?$

A. $0.015 A$
B. $0.025 A$
C. $0.010 A$
D. $0.005 A$

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Correct answer: A — $0.015 A$

Solution

Total current I = \frac{V _{in} - V _{z}}{R _{s}} = \frac{5}{200} = 0.025 A . Load current I_{L} = \frac{V _{z}}{R _{L}} = \frac{10}{1000} = 0.010 A . Zener current I_{z} = I - I_{L} = 0.025 - 0.010 = 0.015 A .

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A Zener diode with a breakdown voltage of Vz​=10V is connected in a voltage regulator circuit with a series resistance Rs​=200Ω and a load resistance RL​=1kΩ. If the input voltage is Vin​=15V, what is the current through the Zener diode?

Solution

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$A Zener diode with a breakdown voltage of V_{z} = 10 V is connected in a voltage regulator circuit with a series resistance R_{s} = 200 Ω and a load resistance R_{L} = 1 k Ω . If the input voltage is V_{in} = 15 V, what is the current through the Zener diode?$