In an intrinsic semiconductor at room temperature, the number of electrons and holes are equal. If the number density of charge carriers is 1.5 times 10 to the power 16 per cubic meter, what is the conductivity if electron mobility is 0.13 and hole mobility is 0.05 square meters per volt second?

A. 0.432 , S/m — Conductivity is given by sigma equals e times n_i times (mu_e plus mu_h). Using e equals 1.6 times 10 to the power minus 19, we calculate 1.6 times 10 to the power minus 19 times 1.5 times 10 to the power 16 times 0.18.

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$In an intrinsic semiconductor at room temperature, n_{e} = n_{h} = n_{i} = 1.5 \times 1 0^{16} m^{- 3} . If electron mobility μ_{e} = 0.13 m^{2} V^{- 1} s^{- 1} and hole mobility μ_{h} = 0.05 m^{2} V^{- 1} s^{- 1}, what is the conductivity?$

A. $0.432 S/m$
B. $0.384 S/m$
C. $0.512 S/m$
D. $0.216 S/m$

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Correct answer: A — $0.432 S/m$

Solution

σ = e n_{i} (μ_{e} + μ_{h}) = (1.6 \times 1 0^{- 19}) \times (1.5 \times 1 0^{16}) \times (0.13 + 0.05) = 2.4 \times 1 0^{- 3} \times 0.18 = 0.432 S/m .

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In an intrinsic semiconductor at room temperature, ne​=nh​=ni​=1.5×1016m−3. If electron mobility μe​=0.13m2V−1s−1 and hole mobility μh​=0.05m2V−1s−1, what is the conductivity?

Solution

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$In an intrinsic semiconductor at room temperature, n_{e} = n_{h} = n_{i} = 1.5 \times 1 0^{16} m^{- 3} . If electron mobility μ_{e} = 0.13 m^{2} V^{- 1} s^{- 1} and hole mobility μ_{h} = 0.05 m^{2} V^{- 1} s^{- 1}, what is the conductivity?$