In an intrinsic semiconductor at room temperature, the number of free electrons is 10 to the power 16 per cubic meter. If the mobility of electrons is 0.13 square meters per volt-second and the mobility of holes is 0.05 square meters per volt-second, what is the conductivity of the semiconductor?

A. 0.288 , S/m — The conductivity of an intrinsic semiconductor is given by the formula sigma equals e times n times (mu_e plus mu_h). Substituting the given values, we calculate the result.

JEE Main · PhysicsHard

$In an intrinsic semiconductor at room temperature, the number of free electrons is n_{e} = 1 0^{16} m^{- 3} . If the mobility of electrons is μ_{e} = 0.13 m^{2} / V \cdot s and the mobility of holes is μ_{h} = 0.05 m^{2} / V \cdot s, what is the conductivity σ of the semiconductor? (Take e = 1.6 \times 1 0^{- 19} C)$

A. $0.288 S/m$
B. $0.144 S/m$
C. $0.576 S/m$
D. $0.072 S/m$

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Correct answer: A — $0.288 S/m$

Solution

The conductivity is σ = e n_{i} (μ_{e} + μ_{h}) . Substituting the values: σ = (1.6 \times 1 0^{- 19}) \times 1 0^{16} \times (0.13 + 0.05) = 1.6 \times 1 0^{- 3} \times 0.18 = 0.288 S/m .

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In an intrinsic semiconductor at room temperature, the number of free electrons is ne​=1016m−3. If the mobility of electrons is μe​=0.13m2/V⋅s and the mobility of holes is μh​=0.05m2/V⋅s, what is the conductivity σ of the semiconductor? (Take e=1.6×10−19C)

Solution

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